Algebraic Structures
(代数系)
Discrete Mathematics I
11th lecture, Dec. 12, 2014
http://www.sw.it.aoyama.ac.jp/2014/Math1/lecture11.html
Martin J. Dürst
© 2006-14 Martin
J. Dürst 青山学院大学
Today's Schedule
- Summary and homework for last lecture
- Algebraic Structures
- Groups
- Rings, fields, latices
Summary of Last Lecture
We defined the following properties of binary relations:
- Reflexive:
∀x∈A:xRx;
∀x∈A: (x, x) ∈
R
- Symmetric: ∀x, y ∈A: xRy
⇔ yRx;
∀x, y ∈A: (x, y)
∈ R ⇔ (y, x) ∈ R
- Antisymmetric: ∀x, y ∈A:
xRy ∧ yRx ⇒ x=y
- Transitive: ∀x, y, z ∈A:
xRy ∧ yRz ⇒ xRz
A relation that is reflexive, antisymmetric, and transitive is a (partial)
order relation.
A relation that is reflexive, symmetric, and transitive is an equivalence
relation.
Unsubmitted Homework?
Homework submitted in paper form is listed as unsubmitted at http://moo.sw.it.aoyama.ac.jp.
Do not worry about this.
Video
Please use the video recordings!
Often they are already available on Monday.
Investigate all combinations of the four properties of relations introduced
in this lecture (reflexive, symmetric, antisymmetric, transitive). For each
combination, give a minimal example or explain why such a combination is
impossible.
Hint: There are 16 combinations. Two combinations are impossible. Two
combinations need a set of four elements for a minimal example. Three
combinations need a set of two elements for a minimal example. Two combinations
need a set of one element for a minimal example. The other combinations need a
set of three elements for a minimal example.
Hint: Use {a, b, c} for a set with three
elements.
Hint: Present the 16 combinations in a table similar to the tables used in
the homework of lecture 4.
Homework Solution
[都合により削除]
Algebraic Structure
Very general view on mathematical objects
- One (or more) set(s)
- One (or more) operation(s) between the elements of the set(s)
Condition: The results of the operation(s) also have to be an element of
the set(s)
- One (or more) axioms
- Proof of theorems and properties from the axioms
Example of Algebraic Structure: Group
- One set (A)
- One binary operation (∘; ∀b,c∈A:
b∘c∈A)
- Three axioms:
- Associativity
(∀b,c,d∈A:
(b∘c)∘d =
b∘(c∘d))
- (existence of a) unit element e
(∃e∈A: ∀b∈A:
e∘b = b =
b∘e)
- (existence of an) inverse element b' (∀b∈A:
∃b'∈A: b∘b' =
e = b'∘b)
- Note: Commutativity is not necessary
The Integers with Addition as a Group
- Set: ℤ (integers)
- Operation: + (addition)
- Associativity:
∀b,c,d∈ℤ:
(b+c)+d =
b+(c+d)
- Unit element: 0
- Inverse element: b' = -b
The Reals with Multiplication as a Group
- Set: ℝ-{0} (real numbers without 0)
- Operation: · (multiplication)
- Associativity:
∀b,c,d∈(ℝ-{0}):
(b·c)·d =
b·(c·d)
- Unit element: 1
- Inverse element: b' = 1/b
The Positive Reals with Multiplication as a Group
- Set: ℝ+ (positive real numbers)
- Operation: · (multiplication)
- Associativity:
∀b,c,d∈ℝ+:
(b·c)·d =
b·(c·d)
- Unit element: 1
- Inverse element: b' = 1/b
Permutations
- There are n! permutations of elements from a set S
with size |S|=n
- Permutations can be seen as ordered selections
Example: From the set {Aoyama, Sagamihara} we can create the permutations
(Aoyama, Sagamihara) and (Sagamihara, Aoyama)
Example: From the set {cat, dog, horse, cow}, we can select the permutation
(dog, cow, cat, horse) (and 23 others)
Permutations as Exchanges
- Permutations can be seen as ways to exchange elements
Example: For a touple/list with two elements, we there are two
permutations:
- One permutation that keeps the same order (1, 2)
- One permutation that changes the order of the elements (2, 1)
- We denote such permutations by assuming we start with a touple of the
first n integers ((1, 2)) and show the result of the
permutation
- Example: The touple (cat, dog, horse, cow), when permuted with the
permutation (2, 4, 1, 3), results in (dog, cow, cat, horse)
Composition of Permutations
- Permutations, when seen as exchanging elements, can be composed
- We use ∘ to denote composition
- Example: (2, 4, 1, 3) ∘ (1, 4, 2, 3) = (2, 3, 4,
1)
- Composition of permutations can be show by using cards
- Cut out and use the cards at permutations.svg
Symmetric Groups
- The permutations of sets of size n together with composition
form a group:
- All compositions of permutations result in another permutation
- Permutations are associative
- The unit element is (1, 2, 3, 4, ...)
- Each permutation has an inverse
Example: The inverse of (2, 4, 1, 3) is (3, 1, 4,
2)
- Commutativity doesn't hold
Example: (2, 4, 1, 3) ∘ (1, 4, 2, 3) = (2, 3, 4,
1)
(1, 4, 2, 3) ∘ (2, 4, 1, 3) = (4, 3, 1,
2)
- These groups are called symmetric groups of order
n
Algebraic Structures Related to Groups
- An Abelian group is a group where the operation is also
commutative
Examples:
- (ℤ; +): Integers with addition
- (ℝ-{0}; ·) Reals (excluding 0) with multiplication
- A semigroup is a group without unit element or inverse
elements
More Algebraic Structures
- Ring: Two operations, 'addition' and 'multiplication'; forms an Abelian
group under addition and a semigroup under multiplication, and addition
distributes over multiplication.
Examples: ℝ, ring of polynomials
- Field
- Lattice: Two operations; both operations are associative and commutative,
and respect absorbtion laws
This Week's Homework
Deadline: December 18, 2014 (Thursday), 19:00.
Format: A4 single page (using both sides is okay; NO cover
page), easily readable handwriting (NO printouts), name (kanji
and kana) and student number at the top right
Where to submit: Box in front of room O-529 (building O, 5th floor)
Create a table of the symmetric group of order 3. Structure the table so
that it looks like a multiplication table, with a row and a column for each
permutation. Use lexical order for the permutations.
Glossary
- algebraic structure
- 代数系
- group
- 群
- group theory
- 群理論
- symmetric group
- 対称群
- Abelian group
- アベル群、可換群
- semigroup
- 半群
- ring
- 環
- polynomial
- 多項式
- field
- 体
- lattice
- 束
- multiplication table
- 九九 (表)