Mathematical Induction and Other Proof
Methods
(数学的帰納法などの証明方法)
Discrete Mathematics I
14th lecture, Jan. 13, 2016
http://www.sw.it.aoyama.ac.jp/2016/Math1/lecture14.html
Martin J. Dürst
© 2006-16 Martin
J. Dürst Aoyama Gakuin
University
Today's Schedule
- Remaining Schedule
- Digit sums and digital roots
- Proof Methods
- Mathematical Induction
- Student Survey
Remaining Schedule
- January 13: this lecture (makeup class)
- January 20: 15th lecture
- January 27, 11:10-12:35: Final exam
Questions about Final Exam
Remainder Calculation: More Examples
318 mod 7 = ?
318 = (33)6 =
276 ≡(mod 7)
(-1)6 = 1
4110 mod 37 = ?
4110 ≡(mod 37)
410 = 220 = 324 ≡(mod
37) (-5)4 = 252
≡(mod 37) (-12)2 = (6 · 2)2 = 36 ·
4 ≡(mod 37) (-1) · 4 = -4 ≡(mod 37)
33
Digit Sum and Digital Root
Digit sum: Sum of all of the digits of a number
Digital root: Single-digit result of repeatedly calculating the digit sum
Example in base 10:
The digit sum of 1839275 is 1+8+3+9+2+7+5 = 35
The digit sum of 35 is 3+5 = 8
The digital root of 1839275 is 8
Example in base 16:
The digit sum of A8FB is A+8+F+B (10+8+15+11) = (44) 2C
The digit sum of 2C is 2+C (2+12) = (14) E
The digital root of A8FB is E
Application of Congruence: Casting out Nines
- The digital root of a number n in base b is equal
to n mod (b-1)
(dr(nb) = n mod
(b-1))
- Reason: For n =
dk...d1d0
= dk×bk+
d (k-1)×b (k-1)+...+d1×b1+d0×b0,
because bm ≡(mod
(b-1)) 1m = 1, n
≡(mod (b-1)) dk+
d(k-1)+...+d1+d0
- If b=10, then b-1=9
- Example in base 10: 1839275 mod 9 = 8
- Example in base 16: A8FB mod F = E
- This can be used for cross-checking the result of an arithmetic
operation:
a · b = c ⇒ dr(dr(a) ·
dr(b)) = dr(c)
a · b ≠ c ⇐ dr(dr(a) ·
dr(b)) ≠ dr(c)
- Example (homework): Only one of the two equations below is correct. Which
one?
2485938 · 4962483 = 12336425064054
2354987 · 2498472 = 5883469079864
About the Handout
- From a (famous) book about (formal) language theory
Please ignore pieces about language theory and automata theory
- Selected because it is general and easily readable
- Sometimes, is uses a different mathematical "dialect"
- The contents is part of the final exam
Importance of Proofs
- Very important tool for Mathematics
(the goal of Mathematics is to prove as many useful and interesting
theorems and properties from very few axioms and definitions)
- For computer science and information technology:
- Proofs of properties of data structures
- Proofs of correctness or other properties of algorithms
- Proofs of correctness or other properties (e.g. speed) of a
program
- Proofs of correctness of program transformations
How Detailled Should a Proof Be?
- Intuition
- (Program) test: Individual test cases
- Level of detail of a proof:
- Rough proof
Example: x + (y + 1) = (x + 1) +
y
- Detailled proof
Example: x + (y + 1) = (commutativity of
addition)
x + (1 + y) =(associativity of
addition) (x + 1) + y
- How to express proofs:
- Mostly textual proof
- Proof using formulæ
- Automatically verified proof
Proof Methods
- Deductive proof (proof by deduction)
- Inductive proof (proof by induction)
- Proof by contradiction
- Proof by counterexample
- Proof about sets
- Proof by enumeration
Proofs and Symbolic Logic
(S is the the theorem to be proven, expressed as a proposition or
predicate)
- Deductive proof: (H ∧
(H→S)) ⇒ S, etc.
- Inductive proof: S(0) ∧ (∀k∈ℕ:
S(k) → S(k+1)) ⇒
(∀n∈ℕ: S(n))
- Proof by contradiction: (¬S→S) ⇒ S
Confirmation:
S |
¬S |
¬S→S |
(¬S→S) → S |
F |
T |
F |
T |
T |
F |
T |
T |
- Proof by counterexample:
(∃x:¬S(x)) ⇒ ¬∀x:
S(x)
- Proof by enumeration: example: truth table
Deduction and Induction
- Deduction: Conclude some specific fact
from some general law
- Induction: Infer some general law from some sample observations
- Mathematical induction
- Goal: Proof of some property about (almost) all parts of some
structure
- The integers are the most frequent "structure", but also tree
structures,...
- Mathematical induction can actually be classified as some kind of
deduction, not induction
Applications of Mathematical Induction
Applications of mathematical induction in information technology:
- Design and proof of properties of algorithms and data structures
- Proofs about programs:
The Two steps of Mathematical Induction
S(0) ∧ (∀k∈ℕ: S(k) →
S(k+1)) ⇒ (∀n∈ℕ:
S(n))
- Base case (basis (step): proof of S(0)
- Inductive step (induction, inductive case): proof of
∀k∈ℕ: S(k) →
S(k+1)
- (inductive) Assumption: clearly state S(k)
- Actual proof of inductive step
Method: Formula manipulation so that the assumption can be used
Simple Example of Mathematical Induction
Look at the following equations:
1 = 1
1 + 3 = 4
1 + 3 + 5 = 9
1 + 3 + 5 + 7 = 16
1 + 3 + 5 + 7 + 9 = 25
Express the general rule contained in the above additions as a
hypothesis.
Prove the hypothesis using Mathematical induction.
Hypothesis
- The right side of the equations is m2
- The left side is the equations is the sum of the m smallest
(consecutive) odd numbers
- Hypothesis: The sum of the m smallest odd numbers is
m2
∀n≥0: ∑ni=0
2i+1 = (n+1)2
Proof
Basis:
Prove the property for n = 0:
∑0i=0 2i+1 = 1 =
12
Induction:
Inductive assumption: Assume that the property is true for some
k≥0: ∑ki=0
2i+1 = (k+1)2
Show that the property is true for k + 1:
∑(k+1)i=0 2i+1 =
(k+2)2
[start with right side]
(k+2)2 [expansion]
= k2 + 4k + 4 [arithmetic]
= k2 + 2k +1 + 2k + 3
[arithmetic]
= (k+1)2 + 2(k+1) + 1 [use
assumption]
= ∑ki=0 (2i+1) +
2(k+1) + 1 [property of ∑]
= ∑(k+1)i=0 2i+1
Q.E.D.
Variations of Mathematical Induction
- Start with S(1) or S(2),... instead of
S(0)
S(b) ∧ (∀k∈ℕ, k≥b:
S(k) → S(k+1)) ⇒
(∀n∈ℕ, n≥b:
S(n))
We can interpret this as proving T(n-b) =
S(n), so that we again start at 0
- In the proof of step 2 for S(k+1), use not only
S(k), but also some or all S(j)
where j≤k
(this is called strong induction or complete
induction)
S(0) ∧ (∀k∈ℕ: (∀i
(0≤i≤k): S(i)) →
S(k+1)) ⇒ ∀n∈ℕ:
S(n)
- Limit the proof to some subset of integers (examples: even numbers only,
2m only)
- Proof not about integers, but about something that can be ordered using
integers
- Branching tree structure or some other structure (e.g. (half) order)
Homework
(no need to submit)
- Answer the question on the slide "Application of Congruence: Casting out
Nines"
- Find out the problem in the following proof:
Theorem: All n lines on a plane that are not parallel to each
other will cross in a single point.
Proof:
- Base case: Obviously true for n=2
- Induction:
- Assumption: k lines cross in a single point.
- For k+1 lines, both the first k lines and
the last k lines will cross in a single point, and this
point will have to be the same because it is shared by
k-1 lines.
- Read the handout
- Find a question regarding past examinations that you can ask in the next
lecture.
Student Survey
(授業改善のための学生アンケート)
WEB Survey
お願い:
自由記述に必ず良かった点、問題点を具体的に書きましょう
(例: 「英語をやめてほしい」のではなく、「Glossary を ...
に改善してください」)
Glossary
- digit
- 数字、桁
- digit sum
- 数字和
- digital root
- 数字根
- casting out nines
- 九去法
- (formal) language theory
- 言語理論
- automata theory
- オートマトン理論
- proof
- 証明
- to prove
- 証明する
- data structure
- データ構造
- intuition
- 直感
- test case
- テスト・ケース
- deductive proof
- 演繹的証明
- inductive proof
- 帰納的証明
- proof by contradiction
- 背理法
- proof by counterexample
- 反例による証明
- proof about sets
- 集合についての証明
- proof by enumeration
- 列挙による「証明」
- mathematical induction
- 数学的帰納法
- structure
- 構造
- loop
- 繰返し
- base case
- 基底
- inductive step
- 帰納
- inductive assumption
- (帰納の) 仮定
- recursion
- 再帰
- hypothesis
- 仮説
- equation
- 方程式
- consecutive
- 連続的な
- odd (number)
- 奇数
- inductive assumption
- (帰納の) 仮定
- strong induction
- 完全帰納法 (または累積帰納法)
- parallel
- 平行