Asymptotic Time Complexity and Big-O
Notation
(漸近的計算量と O 記法)
Data Structures and Algorithms
3rd lecture, October 4, 2018
http://www.sw.it.aoyama.ac.jp/2018/DA/lecture3.html
Martin J. Dürst
© 2009-18 Martin
J. Dürst 青山学院大学
Today's Schedule
- Summary/leftovers from last lecture, last week's homework
- Comparing execution times: From concrete to abstract
- Classification of Functions by Asymptotic Growth
- Big-O notation
Summary of Last Lecture
- There are many ways of describing algorithms: natural language text,
diagrams, pseudocode, programs
- Each description has advantages and disadvantages
- Pseudocode is close to structured programming, but ignores unnecessary
details
- In this course, we will use Ruby as "executable pseudocode"
- The main criterion to evaluate algorithms is time complexity as a
function of the number of (input) data items
- Time complexity is the most important criterion when comparing
algorithms
Leftovers from Last Lecture
Last Week's Homework 1: Example for
Asymptotic Growth of Number of Steps
How to Derive Steps from (Pseudo)Code
- Identify basic operations (arithmetic operations, assignments,
comparisons,...)
- Count or calculate number of times each operation is executed
- If there is a choice, use the worst case
(e.g. for linear search, the 'not found' case)
- For branches, count the worst branch
- For loops, include the loop logic and multiply by number of times the
loop is executed
- For functions, include some steps for function overhead and multiply by
number of times the function is called
Comparing Execution Times: From Concrete to Abstract
Very concrete
- Measure actual execution time
- Count operation steps
- Estimate worst case number of steps
- Think about asymtotic behavior
Very abstract
Estimate Worst Case Number of Steps
Thinking in Terms of Asymptotic Growth
- The execution time of an algorithm and the number of executed steps
depend on the size of the input (the number of data items in the input)
- We can express this dependency as a function:
f(n) (n is the size of the input)
- Rules for comparing functions:
- Concentrate on what happens when n increases (gets really
big)
→ Ignore special cases for small n
→ Ignore constant(-time) differences (example: initialization
time)
- Concentrate on the essence of the algorithm
→ Ignore hardware differences and implementation differences
→ Ignore constant factors
⇒ Independent of hardware, implementation details, step counting
details
⇒ Simple expression of essential differences between algorithms
Last Week's Homework 2: Example for
Asymptotic Growth of Number of Steps
Fill in the following table
(use engineering notation (e.g. 1.5E+20) if the numbers get very big;
round liberally, the magnitude of the number is more important than the exact
value)
n |
1 |
10 |
100 |
1'000 |
10'000 |
100'000 |
5n |
5 |
50 |
500 |
5'000 |
50'000 |
500'000 |
n1.2 |
1 |
15.8 |
251.2 |
3'981 |
63'096 |
1'000'000 |
n2 |
1 |
100 |
10'000 |
1'000'000 |
100'000'000 |
1e+10 |
n log2
n |
0 |
33.2 |
664.4 |
9'966 |
132'877 |
1'660'964 |
1.01n |
1.01 |
1.1046 |
2.7 |
20'959 |
1.636e+43 |
1.372e+432 |
Solution to Homework 3: Compare Function Growth
Which function of each pair (left/right column) grows larger if n
increases?
left |
right |
answer |
100n |
n2 |
right (n ≥ 100) |
1.1n |
n20 |
left (n ≥ 1541) |
5 log2 n |
10 log4 n |
same (log2 x = 2
log4 x)
|
20n |
n! |
right (n ≥ 52) |
100·2n |
2.1n |
right (n ≥ 95) |
Using Ruby to Compare Function Growth
- Start
irb
(Interactive Ruby)
- Write a loop:
(start..end).each { |n|
comparison }
- Example of
comparison
: puts n, 1.1**n,
n**20
- Change the
start
and end
values until appropriate
- If necessary, convert integers to floating point numbers for easier
comparison
- Define the factulty function:
def fac(n) n<2 ? 1 : n*fac(n-1)
end
Caution: Use only when you understand which function will eventually grow
larger
Classification of Functions by Asymptotic Growth
Various growth classes with example functions:
- Linear growth: n, 2n+15, 100n-40,
0.001n,...
- Quadratic growth: n2,
500n2+30n+3000,...
- Cubic growth: n3,
5n3+7n2+80,...
- Logarithmic growth: ln n, log2n, 5
log10n2+30,...
- Exponential growth: 1.1n, 2n,
20.5n+1000n15,...
- ...
Big-O Notation: Set of Functions
Big-O notation is a notation for expressing the order of growth of a
function (e.g. time complexity of an algorithm).
O(g): Set of functions with lower or same order of
growth as function g
Example:
Set of functions that grow slower or as slow as n2:
O(n2)
Usage examples:
3n1.5 ∈ O(n2),
15n2 ∈ O(n2),
2.7n3 ∉ O(n2)
Exact Definition of O
∃c>0: ∃n0≥0:
∀n≥n0:
f(n)≤c·g(n) ⇔ f(n)∈O(g(n))
- g(n) is an asymptotic upper bound of
f(n)
- In some references (books, ...):
- f(n)∈O(g(n))
is written
f(n)=O(g(n))
- In this case, O(g(n)) is always on the rigth
side
- However,
f(n)∈O(g(n))
is more precise and easier to understand
- Role of c: Ignore constant-factor differences (e.g. one
computer or programming language being double as fast as another)
- Role of n0: Ignore initialization costs and
behavior for small values of n
Example Algorithms
- The number of steps in linear search is: an +
b
⇒ Linear search has time complexity O(n)
(linear search is O(n), linear search has linear time
complexity)
- The number of steps in binary search is: c log2
n + d
⇒ Binary search has time a complexity of
O(log n)
- Because O(log n) ⊊ O(n),
binary search is faster
Comparing the Execution Time of Algorithms
(from last lecture)
Possible questions:
- How many seconds faster is binary search when compared to linear
search?
- How many times faster is binary search when compared to linear
search?
Problem: These questions do not have a single answer.
When we compare algorithms, we want a simple answer.
The simple and general answer is using big-O notation:
Linear search is O(n), binary search is O(log
n).
Additional Examples for O
Additional Notations: Ω and Θ
- O(g(n)): Set of functions with lower or
same order of growth as g(n)
- Ω(g(n)): Set of functions with larger
or same order of growth as g(n)
- Θ(g(n)): Set of functions with same
order of growth as g(n)
Examples:
3n1.5 ∈ O(n2),
15n2 ∈ O(n2),
2.7n3 ∉ O(n2)
3n1.5 ∉
Ω(n2), 15n2
∈ Ω(n2),
2.7n3 ∈
Ω(n2)
3n1.5 ∉
Θ(n2), 15n2
∈ Θ(n2),
2.7n3 ∉
Θ(n2)
Exact Definitions of Ω and Θ
∃c>0: ∃n0≥0:
∀n≥n0: c·g(n)≤f(n) ⇔
f(n)∈Ω(g(n))
∃c1>0: ∃c2>0:
∃n0≥0:
∀n≥n0:
c1·g(n)≤f(n)≤c2·g(n) ⇔
f(n)∈Θ(g(n))
f(n)∈O(g(n)) ∧
f(n)∈Ω(g(n)) ⇔ f(n)∈Θ(g(n))
Θ(g(n)) =
O(g(n)) ∩
Ω(g(n))
Use of Order Notation
- O: Maximum (worst-case) time complexity of algorithms
- Ω: Minimally needed time complexity to solve a problem
- Θ: Used when expressing the fact that a time complexity is
not only possible, but actually reached
In general as well as in this course, mainly O will be used.
Confirming the Order of a Function
- Method 1: Use the definition
Find appropriatie values for n0 and c, and
check the definition
- Method 2: Use the limit of a function
limn→∞(f(n)/g(n)):
- If the limit is 0:
O(f(n))⊊O(g(n)),
f(n)∈O(g(n))
- If the limit is 0 < d < ∞:
O(f(n))=O(g(n)),
f(n)∈O(g(n))
- If the limit is
∞: O(g(n))⊊O(f(n)),
f(n)∉O(g(n))
- Method 3: Simplification
Simplification of Big-O Notation
- Big-O notation should be as simple as possible
- Examples (for all functions except constant functions, we assume
increasing):
- Constant functions: O(1)
- Linear functions: O(n)
- Quadratic functions: O(n2)
- Cubic functions: O(n3)
- Logarithmic functions: O(log n)
- For polynomials, all terms except the term with the biggest exponent can
be ignored
- For logarithms, the base is left out (irrelevant)
Ignoring Lower Terms in Polynomials
Concrete Example: 500n2+30n ∈
O(n2)
Derivation for general case: f(n) =
dna +
enb ∈
O(na)
[a > b > 0]
Definition of O: f (n) ≤
cg(n) [n >
n0; n0, c > 0]
dna +
enb ≤
cna [a > 0 ⇒
na>0]
d +
enb/na
= d + enb-a
≤ c [b-a < 0 ⇒
limn→∞enb-a
= 0]
Some possible values for c and n0:
- n0 = 1, c ≥
d+e
- n0 = 2, c≥
d+2b-ae
- n0 = 10, c≥
d+10b-ae
Some possible values for concrete example
(500n2+30n):
- n0 = 1, c ≥ 530 →
500n2+30n ≤ 530n2
[n≥1]
- n0 = 2, c ≥ 515 →
500n2+30n ≤ 515n2
[n≥2]
- n0 = 10, c ≥ 503 →
500n2+30n ≤ 503n2
[n≥10]
In general: a > b > 0 ⇒
O(na +
nb) =
O(na)
Ignoring Logarithm Base
How do O(log2 n) and
O(log10 n) differ?
(Hint: logb a = logc
a / logc b =
logc a ·
logb c)
log10 n = log2
n · log10 2 ≅ 0.301 · log2
n
O(log10 n) = O(0.301... · log2 n) =
O(log2 n)
∀ a>1, b>1:
O(loga n) = O(logb n) =
O(log n)
Summary
- To compare the time complexity of algorithms:
- Ignore constant terms (initialization,...)
- Ignore constant factors (differences due to hardware or
implementation)
- Count basic steps executed in the worst case
- Look at asymptotic growth when input size increases
- Asymptotic growth can be expressed with big-O notation
- The time complexity of algorithms can be expressed as O(log
n), O(n), O(n2),
O(2n), ...
Homework
(no need to submit)
Review this lecture's material and the additional handout every
day!
On the Web, find algorithms with time complexity O(1), O(log n),
O(n), O(n log n), O(n2),
O(n3), O(2n), O(n!), and
so on.
Glossary
- big-O notation
- O 記法 (O そのものは漸近記号ともいう)
- asymptotic growth
- 漸近的な増加
- approximate
- 近似する
- essence
- 本質
- constant factor
- 一定の係数、定倍数
- eventually
- 最終的に
- linear growth
- 線形増加
- quadratic growth
- 二次増加
- cubic growth
- 三次増加
- logarithmic growth
- 対数増加
- exponential growth
- 指数増加
- Omega (Ω)
- オメガ (大文字)
- capital letter
- 大文字
- Theta (Θ)
- シータ (大文字)
- asymptotic upper bound
- 漸近的上界
- asymptotic lower bound
- 漸近的下界
- appropriate
- 適切
- limit
- 極限
- polynomial
- 多項式
- term
- (式の) 項
- logarithm
- 対数
- base
- (対数の) 底